Matematika Sekolah Menengah Atas U4=54
U7=2
a. suku kesembilan
b. jumlah 5 suku pertama

U4=54
U7=2
a. suku kesembilan
b. jumlah 5 suku pertama

Penjelasan dengan langkah-langkah:

r^(7-4)=2/54

r³=1/27

r=³√1/27

r=1/3

U9=U7×r²

=2×1/3²

=2×1/9

=2/9

jadikan yang terbaiknya

U4 = 54

U7 = 2

U7 = ar⁶ = 2

U4 = ar³ = 54

ar⁶/ar³ = 2/54

r³ = 1/27

r = ³V(1/27)

r = 1/3

ar³ = 54

a(1/3)³ = 54

a(1/27) = 54

a = 54/(1/27)

a = 54 × 27/1

a = 1458

a] n = 9

Un = ar^(n-1)

U9 = 1458(1/3)^(9-1)

U9 = 1458(1/3)⁸

U9 = 1458(1/6561)

U9 = 2/9

b] n = 5

Sn = a(1 - r^n)/(1 - r)

S5 = 1458(1 - (1/3)⁵)/(1 - 1/3)

S5 = 1458(243/243 - 1/243)/(3/3 - 1/3)

S5 = 1458(242/243)/(2/3)

S5 = 1452/(2/3)

S5 = 1452 × 3/2

S5 = 2178

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